The APsolute RecAP: Chemistry Edition - Le Chatelier’s Principle
02/01/21 • 8 min
Let’s be disruptive: What happens when you disturb the equilibrium of a chemical reaction? Our episode talks you through several different scenarios and their effect on the reaction as well as K and Q: We can add reactant and product (2:01) or remove reactant and products (2:58). We can also change the temperature of our reaction and either add heat (4:29) or lower the temperature (5:35). If we have gaseous, we can also change the pressure by changing the volume of the container (5:59).
Question (7:48): Which reaction is favored if you decrease the volume and have the same number of gaseous particles on reactant and product side?
Thank you for listening to The APsolute RecAP: Chemistry Edition!
(AP is a registered trademark of the College Board and is not affiliated with The APsolute RecAP. Copyright 2021 - The APsolute RecAP, LLC. All rights reserved.)
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Let’s be disruptive: What happens when you disturb the equilibrium of a chemical reaction? Our episode talks you through several different scenarios and their effect on the reaction as well as K and Q: We can add reactant and product (2:01) or remove reactant and products (2:58). We can also change the temperature of our reaction and either add heat (4:29) or lower the temperature (5:35). If we have gaseous, we can also change the pressure by changing the volume of the container (5:59).
Question (7:48): Which reaction is favored if you decrease the volume and have the same number of gaseous particles on reactant and product side?
Thank you for listening to The APsolute RecAP: Chemistry Edition!
(AP is a registered trademark of the College Board and is not affiliated with The APsolute RecAP. Copyright 2021 - The APsolute RecAP, LLC. All rights reserved.)
Website:
EMAIL:
Follow Us:
Previous Episode
The APsolute RecAP: Chemistry Edition - Equilibrium Constant
Try to keep your balance! The episode starts with an analogy of villagers commuting from Moleville to Chemtown (0:59). Tying it to a chemical reaction, we define equilibrium as the point where the rate of the forward and the rate of the reverse reaction are the same (1:43). To determine if, at equilibrium, a reaction has more reactants or products, we can calculate the equilibrium constant, capital K (3:59) and write the equilibrium expression (4:34). The magnitude of K tells us if a reaction favors the products or the reactants (5:35). To determine if a reaction is at equilibrium, we can calculate Q (6:12).
Question (8:14): The equilibrium constant for a known reaction is K = 150. What would the value for K’ be if you’d reverse the reaction at the same temperature?
Thank you for listening to The APsolute RecAP: Chemistry Edition!
(AP is a registered trademark of the College Board and is not affiliated with The APsolute RecAP. Copyright 2021 - The APsolute RecAP, LLC. All rights reserved.)
Website:
EMAIL:
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Next Episode
The APsolute RecAP: Chemistry Edition - Solubility Equilibria
Our episode starts with addressing the question: What IS solubility? (1:19). The episode introduces solubility equilibria with respect to the Solubility-Product Constant, K, expression (1:57) and discussion how its magnitude relates to solubility (3:05). If you have the Ksp you can calculate the molar solubility - in mol/L - as well as the mass solubility in g/L (4:35). Comparing K to Q let’s you determine if a precipitate forms (5:58).
Question: How does a common ion affect the solubility of a salt?
Thank you for listening to The APsolute RecAP: Chemistry Edition!
(AP is a registered trademark of the College Board and is not affiliated with The APsolute RecAP. Copyright 2021 - The APsolute RecAP, LLC. All rights reserved.)
Website:
EMAIL:
Follow Us:
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